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Grades 9–12 · Machines

How does an electric motor make a shaft turn?

A fan's spinning shaft begins with forces on a coil of wire. In a simplified brushed direct-current motor, the coil sits between magnetic poles. Current runs in opposite directions along its opposite sides, so the magnetic field pushes those sides in opposite directions and transfers electrical energy into rotation.

Those pushes do not cancel their turning effects. They act on different sides of the shaft: one side is pushed one way and the other the opposite way, like two hands turning a steering wheel. Together they create torque, the turning effect of a force. Several wire turns add their contributions.

As the coil rotates, its orientation changes and so does its torque. If its current simply kept the same direction, the turning effect would eventually reverse. A commutator, the current reverser, switches the coil’s connections each half-turn. Momentum carries the rotor through positions where this ideal single coil has zero torque, while the reversed current supports continued turning.

For a flat coil, torque magnitude is N × B × I × A × sin θ. N counts turns, B is field strength, I is current, A is coil area, and θ is the angle between the field and the coil’s perpendicular direction. At the pictured maximum-torque orientation, 20 turns, 0.5 tesla, 1 ampere and 0.02 square meter give 0.2 newton meter.

The current arrows and the into-page and out-of-page force symbols show opposite pushes on different coil sides. The current reverser supports continued turning, and the upper shaft end defines the clockwise view.

M08 visual explanationIdeal motor snapshot at maximum torque: 20 turns, 0.5 T magnetic field and coil area 0.02 square meter. At 1 A the torque magnitude is 0.2 N m, clockwise viewed from the upper shaft end. The field points right. With original polarity, conventional current flows up the left side and down the right, giving left-side force into the page and right-side force out. Reversing polarity reverses those forces. The current reverser supports continued turning.Opposite forces turn a current-carrying coilBlue arrows: conventional current20 turns · 0.5 T · 0.02 m²Magnetic fieldNSForceinto pageForceout of pageCoil + shaftCurrent reverser1 A supply0.2 N m · clockwise from upper shaft end

The current arrows and the into-page and out-of-page force symbols show opposite pushes on different coil sides. The current reverser supports continued turning, and the upper shaft end defines the clockwise view.

M08 portrait visual explanationMaximum-torque motor snapshot: 20 turns, 0.5 tesla, 1 ampere, coil area 0.02 square meter. In the rightward field, current goes up the left coil side and down the right. Left force is into the page and right force out. Torque is 0.2 newton meter clockwise viewed from the upper shaft end.Motor at maximum torque20 turns · 0.5 T · 1 ACoil area: 0.02 m²Field: N to SNSCurrent reverser1 A supplyLeft force: into pageRight force: out of pageTorque: 0.2 N mClockwise viewed fromthe upper shaft end.
Opposite currents in the coil sides create a turning pair of forces. At this maximum-torque orientation, the stated inputs give 0.2 newton meter of clockwise torque when viewed from the upper shaft end.

The pictured torque is an instantaneous turning effect, not a speed prediction. Load, resistance and losses affect a real motor's motion, while rotation induces an opposing voltage called back emf that changes current. Fixing the coil's orientation and current lets this illustration isolate how a pair of forces turns a shaft.

About this explanation

Starting knowledge: Use algebraic products and reason about a coil in a magnetic field.

Sources

  • OpenStax — Motors, Generators, and Transformers
  • OpenStax — 11.5 Force and Torque on a Current Loop
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